Reduction by `LiAlH_4` of hydrolysed product of an ester gives

Options

A. (a) two acids
B. (b) two aldehydes
C. (c) one molecule of alcohol and another of carboxylic acid
D. (d) two alcohols

Explanation

To solve the question regarding the reduction by lithium aluminium hydride (LiAlH₄) of the hydrolyzed product of an ester, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Ester**:
Let's consider a general ester represented as R-COOR'. Here, R and R' can be any alkyl groups.

**Hint**: Remember that an ester consists of a carbonyl group (C=O) adjacent to an ether group (C-O-R).

2. **Hydrolysis of the Ester**:
When the ester undergoes hydrolysis (reaction with water), it breaks down into a carboxylic acid and an alcohol. The reaction can be represented as:
\[ R-COOR' + H_2O \rightarrow R-COOH + R'-OH \]
Here, R-COOH is the carboxylic acid, and R'-OH is the alcohol.

**Hint**: Hydrolysis of esters typically yields a carboxylic acid and an alcohol.

3. **Reduction of Hydrolyzed Products**:
Now, we take the hydrolyzed products, which are R-COOH (carboxylic acid) and R'-OH (alcohol), and reduce them using LiAlH₄.

**Hint**: LiAlH₄ is a strong reducing agent that can reduce carboxylic acids to alcohols.

4. **Reduction Reaction**:
The carboxylic acid (R-COOH) will be reduced to an alcohol (R-CH₂OH) when treated with LiAlH₄. The alcohol (R'-OH) remains unchanged. Thus, the products of the reduction will be:
\[ R-CH_2OH \quad \text{(from carboxylic acid)} \quad \text{and} \quad R'-OH \quad \text{(unchanged alcohol)} \]

**Hint**: The reduction of a carboxylic acid results in the formation of a primary alcohol.

5. **Final Products**:
Therefore, after the reduction, we have two alcohols: R-CH₂OH (from the reduction of the carboxylic acid) and R'-OH (the original alcohol).

**Hint**: The final products depend on the structure of the original ester and can be the same or different alcohols.

### Conclusion:
The final answer is that the reduction of the hydrolyzed product of an ester by LiAlH₄ gives two alcohols. Thus, the correct option is **D: 2 alcohols**.