If Avogadro number `N_(A)` is changed from `6.022xx10^(23) mol^(-1)` to 6`.022xx10^(20) mol^(-1)`, this would change:

Options

A. the definition of mass in units of grams
B. the mass of one mole of carbon
C. the ratio of chemical species to each other in a balanced equation
D. the ratio of elements to each other in a compound

Explanation

To solve the problem, we need to understand the implications of changing Avogadro's number \(N_A\) from \(6.022 \times 10^{23} \, \text{mol}^{-1}\) to \(6.022 \times 10^{20} \, \text{mol}^{-1}\) on the mass of one mole of a substance, specifically carbon in this case.

### Step-by-Step Solution:

1. **Understanding Avogadro's Number**:
Avogadro's number \(N_A\) is the number of particles (atoms, molecules, etc.) in one mole of a substance. The standard value is \(6.022 \times 10^{23} \, \text{mol}^{-1}\).

2. **Mass of One Mole of Carbon**:
The molar mass of carbon is \(12 \, \text{g/mol}\). This means that one mole of carbon (which contains \(N_A\) atoms) weighs \(12 \, \text{g}\).

3. **Calculating Mass per Atom**:
With the standard Avogadro's number:
\[ \text{Mass of one atom of carbon} = \frac{12 \, \text{g}}{6.022 \times 10^{23}} \approx 1.99 \times 10^{-23} \, \text{g} \]

4. **Changing Avogadro's Number**:
If we change Avogadro's number to \(6.022 \times 10^{20} \, \text{mol}^{-1}\), we need to recalculate the mass of one atom of carbon:
\[ \text{Mass of one atom of carbon with new } N_A = \frac{12 \, \text{g}}{6.022 \times 10^{20}} \approx 1.99 \times 10^{-19} \, \text{g} \]

5. **Conclusion**:
The mass of one mole of carbon remains \(12 \, \text{g}\), but the mass of one atom of carbon changes due to the change in Avogadro's number. Therefore, the overall mass of one mole of carbon does not change, but the mass per atom does change significantly.

### Final Answer:
Changing Avogadro's number from \(6.022 \times 10^{23} \, \text{mol}^{-1}\) to \(6.022 \times 10^{20} \, \text{mol}^{-1}\) would change the mass per atom of carbon, but the mass of one mole of carbon remains \(12 \, \text{g}\).