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6.02 xx 10^(20) molecules of urea are pr...

`6.02 xx 10^(20)` molecules of urea are present in 100 mL of its solution. The concentration of urea solution is:

A

0.02 M

B

0.01 M

C

0.001 M

D

0.1 M

Text Solution

Verified by Experts

The correct Answer is:
B
Given , number of molecules of urea `=6.02xx10^(20)`
`:.` Number of moles `=(6.02xx10^(20))/(N_(A))`
`=(6.02xx10^(20))/(6.023xx10^(23))=0.999xx10^(-3)=1xx10^(-3)"mol"`
Volume of the solution
`=100mL=(100)/(1000)L=0.1L` Concentration of urea solution (in mol `L^(-1))`
`=(1xx10^(-3))/(0.1)"mol " L^(-1)`
`=1xx10^(-2)"mol " L^(-1)`
`=0.01 "mol " L^(-1)`
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