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The number of gram molecules of oxygen i...

The number of gram molecules of oxygen in `6.02 xx 10^(24)` CO molecules is/are

A

10 g molecules

B

5 g molecules

C

1 g molecules

D

0.5 molecules

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of finding the number of gram molecules of oxygen in \(6.02 \times 10^{24}\) CO molecules, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Mole Concept**: - One mole of any substance contains \(6.02 \times 10^{23}\) entities (molecules, atoms, etc.). This is known as Avogadro's number. 2. **Determine the Number of Moles of CO**: - Given \(6.02 \times 10^{24}\) CO molecules, we can calculate the number of moles of CO: \[ \text{Number of moles of CO} = \frac{6.02 \times 10^{24} \text{ molecules}}{6.02 \times 10^{23} \text{ molecules/mole}} = 10 \text{ moles of CO} \] 3. **Calculate the Number of Oxygen Atoms**: - Each molecule of CO contains one atom of oxygen. Therefore, the number of moles of oxygen atoms is the same as the number of moles of CO: \[ \text{Number of moles of oxygen atoms} = 10 \text{ moles} \] 4. **Convert Oxygen Atoms to Oxygen Molecules**: - Oxygen (O2) is a diatomic molecule, meaning each molecule consists of two oxygen atoms. To find the number of moles of oxygen molecules, we divide the number of moles of oxygen atoms by 2: \[ \text{Number of moles of O}_2 = \frac{10 \text{ moles of oxygen atoms}}{2} = 5 \text{ moles of O}_2 \] 5. **Conclusion**: - Therefore, the number of gram molecules of oxygen in \(6.02 \times 10^{24}\) CO molecules is \(5\) gram molecules. ### Final Answer: The number of gram molecules of oxygen is **5** gram molecules. ---

To solve the problem of finding the number of gram molecules of oxygen in \(6.02 \times 10^{24}\) CO molecules, we can follow these steps: ### Step-by-Step Solution: 1. **Understanding Mole Concept**: - One mole of any substance contains \(6.02 \times 10^{23}\) entities (molecules, atoms, etc.). This is known as Avogadro's number. 2. **Determine the Number of Moles of CO**: ...
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