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One litre hard water contains 12.00 mg M...

One litre hard water contains 12.00 mg `Mg^(2+)` millieqivalent of washing soda required to remove its hardness is

A

1

B

12.6

C

`1xx10^(-3)`

D

`12.16xx10^(-3)`

Text Solution

Verified by Experts

The correct Answer is:
A
`underset(1 g-eq)(Mg^(2+))+underset(1 g-eq)(Na_(2)CO_(3))toMgCO_(3)+2Na^(+)`
1 g- equivalent of `Mg^(2+)=12g of Mg^(2+)`
=12000 mg of `Mg^(2+)`
Now , 12000 mg of `Mg^(2+)-=1000` milleequivalent of `Na_(2)CO_(3)`
`:.` 12 mg of `Mg^(2+)-=1` milliequivalent of `Na_(2)CO_(3)`
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