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For a reversible reaction, if the concen...

For a reversible reaction, if the concentration of the reactants are doubled, then the equilibrium constant will

A

one-fourth

B

halved

C

doubled

D

the same

Text Solution

Verified by Experts

The correct Answer is:
D
Consider a hypothetical change.
`A+BhArrC+D`
For the reaction.
`K_(eq)=([C][D])/([A][B])`
For the above reaction if concentration of reactions are doubled then the rate of forward reaction increases for a short time but after sometime equilibrium wil established. So concentration has no effect on equilibrium constant. it remains unchanged after increasing the concentration of reactants.
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