Which of the following statements is correct for a reversible process in a state of equilibrium ?

Options

A. (A) `DeltaG=-2.303 RT "log" K`
B. (B) `DeltaG=2.303 RT "log" K`
C. (C) `DeltaG^(@)=-2.303 RT "log" K`
D. (D) `DeltaG^(@)=2.303 RT "log" K`

Answer

A

Explanation

Mathematical expression of the thermodynamic equilibrium is
`DeltaG=DeltaG^(@) + 2.303 RT "log" Q`
At equilibrium when `DeltaG=0 and Q=K`
then `DeltaG=DeltaG^(@)+ 2.303 RT "log" K=0`
`DeltaG^(@)=-2.303 RT "log" K`