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Bond energies of H-H and Cl-Cl are "430 ...

Bond energies of `H-H and Cl-Cl` are `"430 kJ mol"^(-1)` and `"242 kJ mol"^(-1)` respectively. `DeltaH_(f)` for HCl is `"91 kJ mol"^(-1)`.
What will be the bond energy of `H-Cl`?

A

290 `KJ "mol"^(-1)`

B

`380 KJ "mol"^(-1)`

C

`425 KJ "mol"^(-1)`

D

`245 KJ "mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
`DeltaH_("reaction")=Delta_(H-H) + DeltaH_(Cl-Cl)-2DeltaH_(HCl)`
or `DeltaH_(Cl-Cl) =(430+ 240 -(-90))/(2)`
`=(760)/(2)=380 KJ "mol"^(-1)`
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