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Given that C+O(2)rarrCO(2),DeltaH^(@)=-x...

Given that `C+O_(2)rarrCO_(2),DeltaH^(@)=-xKJ` and `2CO+O_(2)rarr2CO_(2),DeltaH^(@)=-yKJ` The enthalpy of formation of carbon monoxide will be

A

`y-2x`

B

`2x-y`

C

`(y-2x)/(2)`

D

`(2x-y)/(2)`

Text Solution

AI Generated Solution

The correct Answer is:
To find the enthalpy of formation of carbon monoxide (CO) from the given reactions, we will use Hess's Law. Let's denote the reactions and their enthalpy changes as follows: 1. Reaction 1: \[ C + O_2 \rightarrow CO_2 \quad \Delta H_1 = -x \text{ kJ} \] 2. Reaction 2: \[ 2CO + O_2 \rightarrow 2CO_2 \quad \Delta H_2 = -y \text{ kJ} \] We need to find the enthalpy of formation of carbon monoxide: \[ C + \frac{1}{2}O_2 \rightarrow CO \quad \Delta H_3 = ? \] ### Step 1: Manipulate the Reactions To derive the enthalpy of formation of CO, we can manipulate the first two reactions. - From Reaction 2, we can divide the entire equation by 2: \[ CO + \frac{1}{2}O_2 \rightarrow CO_2 \quad \Delta H_2' = \frac{-y}{2} \text{ kJ} \] ### Step 2: Add the Reactions Now we can add Reaction 1 and the modified Reaction 2: 1. Reaction 1: \[ C + O_2 \rightarrow CO_2 \quad \Delta H_1 = -x \] 2. Modified Reaction 2: \[ CO + \frac{1}{2}O_2 \rightarrow CO_2 \quad \Delta H_2' = \frac{-y}{2} \] Now, we will subtract the modified Reaction 2 from Reaction 1: \[ C + O_2 - (CO + \frac{1}{2}O_2 \rightarrow CO_2) \] This gives us: \[ C + O_2 - CO - \frac{1}{2}O_2 \rightarrow CO_2 - CO_2 \] ### Step 3: Simplify the Reaction This simplifies to: \[ C + \frac{1}{2}O_2 \rightarrow CO \] ### Step 4: Calculate the Enthalpy Change Now we can calculate the enthalpy change for this reaction: \[ \Delta H_3 = \Delta H_1 + \Delta H_2' = -x + \left(\frac{-y}{2}\right) \] \[ \Delta H_3 = -x + \frac{y}{2} \] ### Step 5: Rearranging the Equation To express \(\Delta H_3\) in a standard form, we can rearrange: \[ \Delta H_3 = \frac{y - 2x}{2} \] Thus, the enthalpy of formation of carbon monoxide is: \[ \Delta H_f (CO) = \frac{y - 2x}{2} \] ### Conclusion The enthalpy of formation of carbon monoxide is: \[ \Delta H_f (CO) = \frac{y - 2x}{2} \]

To find the enthalpy of formation of carbon monoxide (CO) from the given reactions, we will use Hess's Law. Let's denote the reactions and their enthalpy changes as follows: 1. Reaction 1: \[ C + O_2 \rightarrow CO_2 \quad \Delta H_1 = -x \text{ kJ} \] 2. Reaction 2: ...
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