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When (NH(4))(2)Cr(2)O(7) is heated, the ...

When `(NH_(4))_(2)Cr_(2)O_(7)` is heated, the gas evolved is

A

`N_(2)`

B

`NO_(2)`

C

`O_(2)`

D

`N_(2)O`

Text Solution

AI Generated Solution

The correct Answer is:
To determine the gas evolved when ammonium dichromate \((NH_4)_2Cr_2O_7\) is heated, we can follow these steps: ### Step 1: Write the decomposition reaction The first step is to write the balanced equation for the thermal decomposition of ammonium dichromate. When heated, ammonium dichromate decomposes into chromium(III) oxide, water, and nitrogen gas. \[ (NH_4)_2Cr_2O_7 \xrightarrow{\text{heat}} Cr_2O_3 + H_2O + N_2 \] ### Step 2: Identify the products From the balanced equation, we can see that the products of the reaction include: - Chromium(III) oxide \((Cr_2O_3)\) - Water \((H_2O)\) - Nitrogen gas \((N_2)\) ### Step 3: Analyze the gases evolved Among the products, the gas evolved during the heating process is nitrogen gas \((N_2)\). ### Conclusion Thus, the gas evolved when \((NH_4)_2Cr_2O_7\) is heated is nitrogen gas \((N_2)\). ### Final Answer The gas evolved is \(N_2\). ---

To determine the gas evolved when ammonium dichromate \((NH_4)_2Cr_2O_7\) is heated, we can follow these steps: ### Step 1: Write the decomposition reaction The first step is to write the balanced equation for the thermal decomposition of ammonium dichromate. When heated, ammonium dichromate decomposes into chromium(III) oxide, water, and nitrogen gas. \[ (NH_4)_2Cr_2O_7 \xrightarrow{\text{heat}} Cr_2O_3 + H_2O + N_2 \] ...
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