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Among the following complexes, the one w...

Among the following complexes, the one which shows zero crystal field stabilization energy (CFSE) is

A

`[Mn(H_(2)O)_(6)]^(3+)`

B

`[Fe(H_(2)O)_(6)]^(3+)`

C

`[Co(H_(2)O)_(6)]^(2+)`

D

`[Co(H_(2)O)_(6)]^(3+)`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which of the given complexes shows zero crystal field stabilization energy (CFSE), we will follow these steps: ### Step 1: Identify the oxidation states and electron configurations of the metal ions in the complexes. 1. **Manganese Complex (Mn³⁺)**: - Manganese (Mn) has an atomic number of 25. Its ground state electron configuration is [Ar] 4s² 3d⁵. - For Mn³⁺, we remove 3 electrons: 2 from 4s and 1 from 3d. - Thus, the electron configuration for Mn³⁺ is [Ar] 3d⁴. 2. **Iron Complex (Fe³⁺)**: - Iron (Fe) has an atomic number of 26. Its ground state electron configuration is [Ar] 4s² 3d⁶. - For Fe³⁺, we remove 3 electrons: 2 from 4s and 1 from 3d. - Thus, the electron configuration for Fe³⁺ is [Ar] 3d⁵. ### Step 2: Determine the distribution of electrons in the t2g and eg orbitals for each complex. 1. **For Mn³⁺ in a tetrahedral field**: - Tetrahedral complexes have a splitting pattern where t2g (lower energy) and eg (higher energy) orbitals are filled. - With 4 d-electrons, the filling will be as follows: - t2g: 3 electrons (1, 2, 3) - eg: 1 electron (4) - Thus, t2g = 3, eg = 1. 2. **For Fe³⁺ in a tetrahedral field**: - With 5 d-electrons, the filling will be: - t2g: 3 electrons (1, 2, 3) - eg: 2 electrons (4, 5) - Thus, t2g = 3, eg = 2. ### Step 3: Calculate the CFSE for each complex. The formula for CFSE in a tetrahedral complex is: \[ \text{CFSE} = (-0.4 \times \text{t2g electrons}) + (0.6 \times \text{eg electrons}) \] 1. **For Mn³⁺**: \[ \text{CFSE} = (-0.4 \times 3) + (0.6 \times 1) = -1.2 + 0.6 = -0.6 \] 2. **For Fe³⁺**: \[ \text{CFSE} = (-0.4 \times 3) + (0.6 \times 2) = -1.2 + 1.2 = 0 \] ### Step 4: Conclusion From the calculations, we find that the CFSE for Fe³⁺ is 0. Therefore, the complex that shows zero crystal field stabilization energy is the **Fe³⁺ complex**. ### Final Answer: The complex that shows zero crystal field stabilization energy (CFSE) is **the Fe³⁺ complex**. ---

To determine which of the given complexes shows zero crystal field stabilization energy (CFSE), we will follow these steps: ### Step 1: Identify the oxidation states and electron configurations of the metal ions in the complexes. 1. **Manganese Complex (Mn³⁺)**: - Manganese (Mn) has an atomic number of 25. Its ground state electron configuration is [Ar] 4s² 3d⁵. - For Mn³⁺, we remove 3 electrons: 2 from 4s and 1 from 3d. - Thus, the electron configuration for Mn³⁺ is [Ar] 3d⁴. ...
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