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Crystal field stabilization energy for h...

Crystal field stabilization energy for high spin `d^4` octahedral complex is

A

`-1.8Delta_(0)`

B

`-1.6Delta_(0)+P`

C

`-1.2Delta_(0)`

D

`-0.6Delta_(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
(d) Key Idea In case of high spin complex, `Delta_(o)` is small. Than the pairing energy. That means, the energy required to pair up the fourth electorn with the electrons of lower energy d-orbitals would be higher than that required to place the electrons in the higher d-orbital Thus, painng does not occur. For high spin `d^(4)` octahedral complex.

`therefore` Crystal field stabilisation energy
`=(-3xx0.4+1xx0.6)Delta_(o)`
`=(-1.2+0.6)Delta_(o)=-0.6Delta_(o)`
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