Which of the following will exhibit maximum ionic conductivity ?

Options

A. `K_(4)[Fe(CN)_(6)]`
B. `[Co(NH_(3))_(6)]Cl_(3)`
C. `[Cu(NH_(3))_(4)]Cl_(2)`
D. `[Ni(CO)_(4)]`

Explanation

To determine which compound exhibits maximum ionic conductivity, we need to analyze the number of ions produced when each compound is ionized. Ionic conductivity is directly related to the number of ions in solution; the more ions present, the higher the conductivity.

### Step-by-step Solution:

1. **Identify the Compounds**: List the compounds provided in the question. For this example, let's assume the compounds are:
- A: K4[Fe(CN)6]
- B: [Co(NH3)6]Cl2
- C: [Co(NH3)4]Cl2
- D: Ni(Cu)4

2. **Ionization of Each Compound**:
- **Compound A: K4[Fe(CN)6]**
- Upon ionization:
- 4 K⁺ ions + [Fe(CN)6]⁴⁻
- Total ions = 4 (K⁺) + 1 ([Fe(CN)6]⁴⁻) = **5 ions**

- **Compound B: [Co(NH3)6]Cl2**
- Upon ionization:
- 2 Cl⁻ ions + [Co(NH3)6]²⁺
- Total ions = 2 (Cl⁻) + 1 ([Co(NH3)6]²⁺) = **3 ions**

- **Compound C: [Co(NH3)4]Cl2**
- Upon ionization:
- 2 Cl⁻ ions + [Co(NH3)4]²⁺
- Total ions = 2 (Cl⁻) + 1 ([Co(NH3)4]²⁺) = **3 ions**

- **Compound D: Ni(Cu)4**
- This compound does not ionize into separate ions.
- Total ions = **0 ions**

3. **Compare the Total Number of Ions**:
- Compound A: 5 ions
- Compound B: 3 ions
- Compound C: 3 ions
- Compound D: 0 ions

4. **Conclusion**:
- The compound that exhibits maximum ionic conductivity is **Compound A: K4[Fe(CN)6]** since it produces the highest number of ions (5).

### Final Answer:
The compound that will exhibit maximum ionic conductivity is **Option A: K4[Fe(CN)6]**.