The total number possible isomers for the complex compound `[Cu^(II)(NH_(3))_(4) [Pt^(II)CI_(4)]` are

Options

A. 5
B. 6
C. 3
D. 4

Explanation

To determine the total number of possible isomers for the complex compound \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\), we will analyze the coordination isomers that can be formed by the ligands around the central metal ions.

### Step-by-Step Solution:

1. **Identify the Coordination Complexes**:
- The complex consists of two parts: \([Cu^{II}(NH_3)_4]\) and \([Pt^{II}Cl_4]\).
- Copper (Cu) is coordinated with four ammonia (NH₃) ligands.
- Platinum (Pt) is coordinated with four chloride (Cl) ligands.

2. **Understand Coordination Isomers**:
- Coordination isomers are formed when the ligands around the metal centers are interchanged.
- In this case, we can interchange the ligands between the two metal centers (Cu and Pt).

3. **List Possible Isomers**:
- **Isomer 1**: \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\) (4 NH₃ with Cu and 4 Cl with Pt)
- **Isomer 2**: \([Cu^{II}(NH_3)_3Cl][Pt^{II}(NH_3)Cl_3]\) (3 NH₃ with Cu, 1 Cl with Cu, 3 NH₃ with Pt, and 1 Cl with Pt)
- **Isomer 3**: \([Cu^{II}(NH_3)Cl_3][Pt^{II}(NH_3)_3Cl]\) (1 NH₃ with Cu, 3 Cl with Cu, 3 NH₃ with Pt, and 1 Cl with Pt)
- **Isomer 4**: \([Cu^{II}Cl_4][Pt^{II}(NH_3)_4]\) (4 Cl with Cu and 4 NH₃ with Pt)

4. **Count the Isomers**:
- From the above analysis, we can see that there are a total of 4 distinct coordination isomers possible for the given complex.

5. **Conclusion**:
- Therefore, the total number of possible isomers for the complex compound \([Cu^{II}(NH_3)_4][Pt^{II}Cl_4]\) is **4**.

### Final Answer:
The total number of possible isomers is **4**.