`D(+)` glucose reacts with hydroxylamine and yields an oxime. The structure of the oxime would be `:`

Explanation

To determine the structure of the oxime formed when D(+) glucose reacts with hydroxylamine, we can follow these steps:

### Step 1: Identify the structure of D(+) glucose
- D(+) glucose is an aldohexose sugar. Its structure can be represented as:
```
CHO
|
HO-C-H
|
H-C-OH
|
H-C-OH
|
CH2OH
```

### Step 2: Identify the functional group involved in the reaction
- The carbonyl group (C=O) in the aldehyde form of glucose will react with hydroxylamine (NH2OH). The carbonyl carbon is the first carbon in the chain.

### Step 3: Reaction with hydroxylamine
- Hydroxylamine will attack the carbonyl carbon of glucose. The reaction can be summarized as follows:
- The nitrogen of hydroxylamine donates a lone pair to form a bond with the carbonyl carbon.
- This results in the formation of a tetrahedral intermediate.

### Step 4: Formation of the oxime
- In the tetrahedral intermediate, the hydroxyl group (OH) from the carbonyl carbon will be converted to an oxime group (C=N-OH).
- The reaction proceeds with the elimination of water (H2O), leading to the formation of the oxime.

### Step 5: Draw the structure of the oxime
- The final structure of the oxime (glucoxime) can be represented as:
```
CH=N-OH
|
HO-C-H
|
H-C-OH
|
H-C-OH
|
CH2OH
```

### Final Structure of Glucoxime
- The oxime formed from D(+) glucose and hydroxylamine is known as glucoxime, and its structure is characterized by the presence of the C=N-OH functional group.