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A segment of DNA has 120 adenine and 120...

A segment of DNA has 120 adenine and 120 cytosine bases. The total number of nucleotides present in the segment is

A

120

B

240

C

60

D

480

Text Solution

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The correct Answer is:
To find the total number of nucleotides in the given segment of DNA, we can follow these steps: ### Step 1: Identify the number of each base We know from the question that there are: - 120 adenine (A) bases - 120 cytosine (C) bases ### Step 2: Apply Chargaff's Rule According to Chargaff's rule: - The amount of adenine (A) is equal to the amount of thymine (T). - The amount of cytosine (C) is equal to the amount of guanine (G). Since there are 120 adenine bases, there must also be 120 thymine bases. Similarly, since there are 120 cytosine bases, there must also be 120 guanine bases. ### Step 3: Calculate the total number of nucleotides Now, we can calculate the total number of nucleotides by adding the number of each base: - Adenine (A) = 120 - Thymine (T) = 120 - Cytosine (C) = 120 - Guanine (G) = 120 Total nucleotides = A + T + C + G Total nucleotides = 120 + 120 + 120 + 120 Total nucleotides = 480 ### Final Answer The total number of nucleotides present in the segment is **480**. ---
To find the total number of nucleotides in the given segment of DNA, we can follow these steps: ### Step 1: Identify the number of each base We know from the question that there are: - 120 adenine (A) bases - 120 cytosine (C) bases ### Step 2: Apply Chargaff's Rule ...
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