Home
Class 12
CHEMISTRY
In which one of the following species , ...

In which one of the following species , the central atom has the tuype of hybdridiztion which is not the same as that present in other three?

A

`SF_4`

B

`I_3^-`

C

`SbCl_5^(2-)`

D

`PCl_5`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of identifying which species has a different type of hybridization from the others, we can follow these steps: ### Step 1: Identify the Species We need to analyze the hybridization of four species: SF4, I3^-, SbCl5^2-, and PCl5. ### Step 2: Determine the Hybridization of Each Species 1. **For SF4 (Sulfur Tetrafluoride)**: - Sulfur (S) has 6 valence electrons. - It forms 4 bonds with 4 fluorine atoms and has 1 lone pair. - Hybridization = Number of bond pairs + Number of lone pairs = 4 (bond pairs) + 1 (lone pair) = 5. - Therefore, the hybridization of SF4 is **sp³d**. 2. **For I3^- (Triiodide Ion)**: - Iodine (I) has 7 valence electrons. - In I3^-, the central iodine atom forms 2 bonds with 2 other iodine atoms and has 3 lone pairs. - Hybridization = 2 (bond pairs) + 3 (lone pairs) = 5. - Therefore, the hybridization of I3^- is also **sp³d**. 3. **For SbCl5^2- (Antimony Pentachloride Ion)**: - Antimony (Sb) has 5 valence electrons. - In SbCl5^2-, it has gained 2 electrons, giving it 7 valence electrons. - It forms 5 bonds with 5 chlorine atoms and has 1 lone pair. - Hybridization = 5 (bond pairs) + 1 (lone pair) = 6. - Therefore, the hybridization of SbCl5^2- is **sp³d²**. 4. **For PCl5 (Phosphorus Pentachloride)**: - Phosphorus (P) has 5 valence electrons. - It forms 5 bonds with 5 chlorine atoms and has no lone pairs. - Hybridization = 5 (bond pairs) + 0 (lone pairs) = 5. - Therefore, the hybridization of PCl5 is **sp³d**. ### Step 3: Compare the Hybridizations - SF4: sp³d - I3^-: sp³d - SbCl5^2-: sp³d² - PCl5: sp³d ### Conclusion The species with a different type of hybridization is **SbCl5^2-**, as it has sp³d² hybridization, while the others have sp³d hybridization. ### Final Answer **SbCl5^2-** has a different type of hybridization compared to the other three species. ---

To solve the problem of identifying which species has a different type of hybridization from the others, we can follow these steps: ### Step 1: Identify the Species We need to analyze the hybridization of four species: SF4, I3^-, SbCl5^2-, and PCl5. ### Step 2: Determine the Hybridization of Each Species 1. **For SF4 (Sulfur Tetrafluoride)**: ...
Promotional Banner

Similar Questions

Explore conceptually related problems

In which one of the following species , the central atom has the type of hybdridiztion which is not the same as that present in other three?

Which one the following is the species ?

In which of the following species the central atom is sp^3d^2 hybridised?

In which of the following species central atom is not sp^3 hybridized?

Which of the following species have the same shape?

Which of the following species have the same shape?

Which of the following species has O-O bond?

Which one of the following has the largest atomic radius?

In which one of the following compounds does the central atom obey the octet rule ?

Which one of the following has the smallest atomic radius?