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Which molecule has trigonal planar geome...

Which molecule has trigonal planar geometry ?

A

`IF_3`

B

`PCl_3`

C

`NH_3`

D

`BF_3`

Text Solution

AI Generated Solution

The correct Answer is:
To determine which molecule has a trigonal planar geometry, we will analyze the molecular geometry of each given molecule step by step. ### Step 1: Analyze IF3 (Iodine Trifluoride) - **Valence Electrons**: Iodine (I) has 7 valence electrons. Each fluorine (F) has 7 valence electrons. - **Bonding**: Iodine forms 3 bonds with 3 fluorine atoms, using 3 of its valence electrons. - **Lone Pairs**: After forming 3 bonds, iodine has 2 lone pairs remaining. - **Hybridization**: The hybridization is calculated as the sum of bond pairs and lone pairs: - Bond pairs = 3 - Lone pairs = 2 - Total = 3 + 2 = 5 → Hybridization = sp³d - **Geometry**: The molecular shape is T-shaped due to the presence of lone pairs. ### Step 2: Analyze PCl3 (Phosphorus Trichloride) - **Valence Electrons**: Phosphorus (P) has 5 valence electrons. Each chlorine (Cl) has 7 valence electrons. - **Bonding**: Phosphorus forms 3 bonds with 3 chlorine atoms. - **Lone Pairs**: After forming 3 bonds, phosphorus has 1 lone pair remaining. - **Hybridization**: - Bond pairs = 3 - Lone pairs = 1 - Total = 3 + 1 = 4 → Hybridization = sp³ - **Geometry**: The molecular shape is trigonal pyramidal due to the lone pair. ### Step 3: Analyze NH3 (Ammonia) - **Valence Electrons**: Nitrogen (N) has 5 valence electrons. Each hydrogen (H) has 1 valence electron. - **Bonding**: Nitrogen forms 3 bonds with 3 hydrogen atoms. - **Lone Pairs**: After forming 3 bonds, nitrogen has 1 lone pair remaining. - **Hybridization**: - Bond pairs = 3 - Lone pairs = 1 - Total = 3 + 1 = 4 → Hybridization = sp³ - **Geometry**: The molecular shape is also trigonal pyramidal due to the lone pair. ### Step 4: Analyze BF3 (Boron Trifluoride) - **Valence Electrons**: Boron (B) has 3 valence electrons. Each fluorine (F) has 7 valence electrons. - **Bonding**: Boron forms 3 bonds with 3 fluorine atoms. - **Lone Pairs**: After forming 3 bonds, boron has no lone pairs remaining. - **Hybridization**: - Bond pairs = 3 - Lone pairs = 0 - Total = 3 + 0 = 3 → Hybridization = sp² - **Geometry**: The molecular shape is trigonal planar since there are no lone pairs. ### Conclusion Among the analyzed molecules, **BF3 (Boron Trifluoride)** has a trigonal planar geometry.

To determine which molecule has a trigonal planar geometry, we will analyze the molecular geometry of each given molecule step by step. ### Step 1: Analyze IF3 (Iodine Trifluoride) - **Valence Electrons**: Iodine (I) has 7 valence electrons. Each fluorine (F) has 7 valence electrons. - **Bonding**: Iodine forms 3 bonds with 3 fluorine atoms, using 3 of its valence electrons. - **Lone Pairs**: After forming 3 bonds, iodine has 2 lone pairs remaining. - **Hybridization**: The hybridization is calculated as the sum of bond pairs and lone pairs: - Bond pairs = 3 ...
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