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The number of antibonding electron pairs...

The number of antibonding electron pairs in `O_(2)^(2-)` molecular ion on the basic of molecular orbital theory is

A

(a) 5

B

(b) 2

C

(c) 4

D

(d) 6

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The correct Answer is:
To determine the number of antibonding electron pairs in the \( O_2^{2-} \) molecular ion based on molecular orbital theory, we can follow these steps: ### Step 1: Determine the Total Number of Electrons The atomic number of oxygen is 8, meaning each oxygen atom has 8 electrons. For \( O_2 \), which consists of two oxygen atoms, the total number of electrons is: \[ 2 \times 8 = 16 \text{ electrons} \] Since the ion has a \( 2- \) charge, we add 2 more electrons: \[ 16 + 2 = 18 \text{ electrons} \] ### Step 2: Write the Molecular Orbital Configuration According to molecular orbital theory, the order of filling the molecular orbitals for \( O_2 \) and its ions is: 1. \( \sigma_{1s} \) 2. \( \sigma^*_{1s} \) 3. \( \sigma_{2s} \) 4. \( \sigma^*_{2s} \) 5. \( \sigma_{2p_z} \) 6. \( \pi_{2p_x} \) and \( \pi_{2p_y} \) (degenerate) 7. \( \pi^*_{2p_x} \) and \( \pi^*_{2p_y} \) (degenerate) 8. \( \sigma^*_{2p_z} \) ### Step 3: Fill the Electrons in the Molecular Orbitals We fill the molecular orbitals with the 18 electrons: - \( \sigma_{1s} \): 2 electrons - \( \sigma^*_{1s} \): 2 electrons - \( \sigma_{2s} \): 2 electrons - \( \sigma^*_{2s} \): 2 electrons - \( \sigma_{2p_z} \): 2 electrons - \( \pi_{2p_x} \): 2 electrons - \( \pi_{2p_y} \): 2 electrons - \( \pi^*_{2p_x} \): 2 electrons - \( \pi^*_{2p_y} \): 0 electrons (since we have filled 18 electrons) The filling looks like this: - \( \sigma_{1s}^2 \) - \( \sigma^*_{1s}^2 \) - \( \sigma_{2s}^2 \) - \( \sigma^*_{2s}^2 \) - \( \sigma_{2p_z}^2 \) - \( \pi_{2p_x}^2 \) - \( \pi_{2p_y}^2 \) - \( \pi^*_{2p_x}^2 \) - \( \pi^*_{2p_y}^0 \) ### Step 4: Count the Antibonding Electrons The antibonding orbitals are: - \( \sigma^*_{1s} \): 2 electrons - \( \sigma^*_{2s} \): 2 electrons - \( \pi^*_{2p_x} \): 2 electrons - \( \pi^*_{2p_y} \): 0 electrons Total antibonding electrons: \[ 2 + 2 + 2 + 0 = 6 \text{ antibonding electrons} \] ### Step 5: Calculate the Number of Antibonding Electron Pairs Since each pair consists of 2 electrons, the number of antibonding electron pairs is: \[ \frac{6}{2} = 3 \text{ antibonding electron pairs} \] ### Conclusion Thus, the number of antibonding electron pairs in \( O_2^{2-} \) is **3**.

To determine the number of antibonding electron pairs in the \( O_2^{2-} \) molecular ion based on molecular orbital theory, we can follow these steps: ### Step 1: Determine the Total Number of Electrons The atomic number of oxygen is 8, meaning each oxygen atom has 8 electrons. For \( O_2 \), which consists of two oxygen atoms, the total number of electrons is: \[ 2 \times 8 = 16 \text{ electrons} \] Since the ion has a \( 2- \) charge, we add 2 more electrons: ...
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