The ground state electronic configuration of valence shell electrons in nitrogen molecule `(N_2)` is written as
`sigma2 s^2 , sigma^(***)2s^2, sigma2p_x^2 , pi2p_y^2~~pi2p_z^2`
Bond order in nitrogen molecule is

Options

A. 2
B. 1
C. 0
D. 3

Explanation

To find the bond order of the nitrogen molecule (N₂), we will follow these steps:

### Step 1: Identify the Electronic Configuration
The ground state electronic configuration of the valence shell electrons in the nitrogen molecule (N₂) is given as:
- σ2s²
- σ*2s²
- σ2p_x²
- π2p_y²
- π2p_z²

### Step 2: Count the Electrons in Bonding and Antibonding Orbitals
Next, we need to identify how many electrons are in bonding molecular orbitals and how many are in antibonding molecular orbitals.

- **Bonding Molecular Orbitals (BMO)**:
- σ2s: 2 electrons
- σ2p_x: 2 electrons
- π2p_y: 2 electrons
- π2p_z: 2 electrons

Total electrons in bonding orbitals = 2 (σ2s) + 2 (σ2p_x) + 2 (π2p_y) + 2 (π2p_z) = **8 electrons**

- **Antibonding Molecular Orbitals (ABMO)**:
- σ*2s: 2 electrons

Total electrons in antibonding orbitals = 2 (σ*2s) = **2 electrons**

### Step 3: Use the Bond Order Formula
The bond order can be calculated using the formula:
\[ \text{Bond Order} = \frac{(N_b - N_a)}{2} \]
Where:
- \(N_b\) = number of electrons in bonding orbitals
- \(N_a\) = number of electrons in antibonding orbitals

Substituting the values we found:
\[ \text{Bond Order} = \frac{(8 - 2)}{2} = \frac{6}{2} = 3 \]

### Step 4: Conclusion
The bond order of the nitrogen molecule (N₂) is **3**.

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