Home
Class 12
CHEMISTRY
A sp^(3) hybrid orbital contains...

A `sp^(3)` hybrid orbital contains

A

`1/4` s-character

B

`1/2` s-character

C

`1/3` s-character

D

`2/3` s-character

Text Solution

Verified by Experts

The correct Answer is:
A

In `sp^3` hybrid orbital one part, out of four orbital is s-orbital, so it have 25% or `1/4` s-character.
Promotional Banner

Similar Questions

Explore conceptually related problems

A sp3 hybrid orbital contains: what percent of S character

An sp^(3) hybrid orbital possesses

Total number of sp^(2) hybrid orbitals present in the following compound ?

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Smallest Ohat(S)O bond angle is found in :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Correct order of P-P bond length in the following compound is :

According to hybridisation theory, the % s-character in sp, sp^(2) and sp^(3) hybrid orbitals is 50, 33.3 and 25 respectively, but this is not true for all the species. When theta is the bond angle between equivalent hybrid orbitals then % s and p-character in hybrid orbitals (when only s and p-orbitals are involved in hybridisation) can be calculated by the following formula : costheta=(S)/(S-1)=(P-1)/(P) Q. Two elements X and Y combined together to form a covalent compound. If % p-character is found to be 80% in a orbital then the hybridised state of central atom X for the orbital is :

The species in which the cantral atom uses sp^(2) hybrid orbital in its bonding is:

In which of the following the central atom does not use sp^(2) hybrid orbitals in its bonding

In which of the following the central atom use sp^(2) hybrid orbitals in its bonding