Which of the following molecule does not have a linear arrangement of atoms ?

Options

A. `H_2S`
B. `C_2H_2`
C. `BeH_2`
D. `CO_2`

Explanation

To determine which molecule does not have a linear arrangement of atoms, we will analyze the molecular geometry of each given option using hybridization concepts.

### Step-by-step Solution:

1. **Identify the Molecules**: The options provided are H₂S, C₂H₂, BeH₂, and CO₂.

2. **Analyze H₂S**:
- **Valence Electrons**: Sulfur (S) has 6 valence electrons, and each hydrogen (H) has 1 valence electron. Therefore, total valence electrons = 6 + 2(1) = 8.
- **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{1}{2} \left( \text{Valence Electrons of S} + \text{Monovalent Atoms} + \text{Charge} \right) = \frac{1}{2} (6 + 2 + 0) = \frac{8}{2} = 4 \]
This indicates a tetrahedral arrangement.
- **Shape**: H₂S has two lone pairs on sulfur, resulting in a bent shape, not linear.

3. **Analyze C₂H₂**:
- **Structure**: C₂H₂ (ethyne) has a triple bond between the two carbon atoms.
- **Hybridization**: Each carbon is sp hybridized due to the triple bond.
- **Shape**: The molecule is linear.

4. **Analyze BeH₂**:
- **Valence Electrons**: Beryllium (Be) has 2 valence electrons, and each hydrogen has 1. Total = 2 + 2(1) = 4.
- **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{1}{2} (2 + 2 + 0) = \frac{4}{2} = 2 \]
This indicates sp hybridization.
- **Shape**: BeH₂ is linear.

5. **Analyze CO₂**:
- **Valence Electrons**: Carbon (C) has 4 valence electrons, and each oxygen has 6. Total = 4 + 2(6) = 16.
- **Hybridization Calculation**:
\[ \text{Hybridization} = \frac{1}{2} (4 + 0 + 0) = \frac{4}{2} = 2 \]
This indicates sp hybridization.
- **Shape**: CO₂ is linear.

### Conclusion:
Among the given molecules, **H₂S** does not have a linear arrangement of atoms; it has a bent shape due to the presence of lone pairs on the sulfur atom.

### Final Answer:
The molecule that does not have a linear arrangement of atoms is **H₂S**.