Which of the following is most soluble?

Options

A. `Bi_(2)S_(3)(K_(sp)=1xx10^(-70))`
B. `MnS(K_(sp)=7xx10^(-16))`
C. `CuS(K_(sp)=8xx10^(-37))`
D. `Ag_(2)S(K_(sp)=6xx10^(-51))`

Explanation

To determine which of the given compounds is most soluble, we will analyze their solubility products (Ksp). The solubility product is a measure of the maximum amount of a solute that can dissolve in a solution at equilibrium. The higher the Ksp value, the more soluble the compound is.

### Step-by-Step Solution:

1. **Identify the Ksp Values**:
We have the following Ksp values for the compounds:
- Compound A: Ksp = 1 x 10^-70
- Compound B: Ksp = 7 x 10^-16
- Compound C: Ksp = 8 x 10^-37
- Compound D: Ksp = 6 x 10^-51

2. **Compare the Ksp Values**:
To determine which compound is the most soluble, we need to compare the Ksp values. The larger the Ksp value, the greater the solubility of the compound.
- Ksp of Compound B (7 x 10^-16) is greater than Ksp of Compound C (8 x 10^-37).
- Ksp of Compound C (8 x 10^-37) is greater than Ksp of Compound D (6 x 10^-51).
- Ksp of Compound D (6 x 10^-51) is significantly smaller than Ksp of Compound A (1 x 10^-70).

3. **Rank the Compounds by Solubility**:
Based on the Ksp values, we can rank the compounds from most soluble to least soluble:
- Most Soluble: Compound B (7 x 10^-16)
- Next: Compound C (8 x 10^-37)
- Then: Compound D (6 x 10^-51)
- Least Soluble: Compound A (1 x 10^-70)

4. **Conclusion**:
Therefore, the compound with the highest Ksp value, and hence the most soluble, is Compound B (7 x 10^-16).

### Final Answer:
**Compound B is the most soluble.**

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