Haemophilic man marries a normal woman. Their offspring will be

Options

A. all boys haemophilic
B. all normal
C. all girls haemophilic
D. all haemophilic

Explanation

To solve the question regarding the offspring of a hemophilic man and a normal woman, we can follow these steps:

### Step 1: Understand the Genetics of Hemophilia
Hemophilia is a sex-linked recessive disorder that is carried on the X chromosome. In this case, the hemophilic man has the genotype X^hY (where X^h represents the hemophilia allele) and the normal woman has the genotype X^H X^H (where X^H represents the normal allele).

### Step 2: Determine the Gametes
- The hemophilic man can produce two types of gametes: X^h and Y.
- The normal woman can produce two types of gametes: X^H (since both X chromosomes are normal).

### Step 3: Perform the Cross
Now, we can set up a Punnett square to visualize the possible offspring:
- The male gametes (from the hemophilic man): X^h and Y
- The female gametes (from the normal woman): X^H and X^H

The combinations from the Punnett square will be:
1. X^H X^h (female carrier)
2. X^H X^h (female carrier)
3. X^H Y (normal male)
4. X^H Y (normal male)

### Step 4: Analyze the Offspring
From the combinations, we can conclude:
- All daughters (X^H X^h) will be carriers of hemophilia but will not express the condition.
- All sons (X^H Y) will be normal and will not have hemophilia.

### Conclusion
Thus, the offspring of a hemophilic man and a normal woman will be:
- All normal children (with daughters being carriers).

### Final Answer
The correct option is: **All normal offspring.**

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