A cross between pure tall Pea plant with green pods and dwarf Pea Plant with yellow pods will produce short `F_(2)` plant out of 16

Options

A. 9
B. 3
C. 4
D. 1

Explanation

To solve the problem of how many short F2 plants will be produced from a cross between a pure tall pea plant with green pods and a dwarf pea plant with yellow pods, we can follow these steps:

### Step 1: Define the Traits and Genotypes
- **Tall (T)** is dominant over **dwarf (t)**.
- **Green pod (Y)** is dominant over **yellow pod (y)**.
- The pure tall plant with green pods will have the genotype **TTYY**.
- The dwarf plant with yellow pods will have the genotype **ttyy**.

### Step 2: Determine the Gametes
- The gametes from the pure tall plant (TTYY) will be **TY**.
- The gametes from the dwarf plant (ttyy) will be **ty**.

### Step 3: Perform the F1 Cross
- When we cross the gametes, we get the F1 generation:
- **F1 genotype**: All offspring will be **TtYy** (tall with green pods).

### Step 4: Selfing the F1 Generation to Obtain F2
- Now, we will self-fertilize the F1 plants (TtYy x TtYy) to produce the F2 generation.

### Step 5: Create a Punnett Square for the F2 Generation
- We will set up a Punnett square for the dihybrid cross (TtYy x TtYy) which will result in:
- **TTYY, TTYy, TtYY, TtYy, Ttyy, ttYY, ttYy, ttyy**.

### Step 6: Determine the Phenotypic Ratio
- The phenotypic ratio from the F2 generation will be:
- **9 Tall Green (TTYY, TTYy, TtYY, TtYy)**
- **3 Tall Yellow (TTyy, Ttyy)**
- **3 Dwarf Green (ttYY, ttYy)**
- **1 Dwarf Yellow (ttyy)**

### Step 7: Count the Short Plants
- Short plants (dwarf) are represented by the genotypes **ttyy, ttYy, ttYY**.
- From the ratio, we can see that there are **4 dwarf plants** (3 Dwarf Green + 1 Dwarf Yellow).

### Conclusion
- Therefore, out of 16 F2 plants, **4 will be short (dwarf)**.

### Final Answer
The answer to the question is **4 short F2 plants out of 16**.

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