A colourblind woman marries a normal visioned male. In the offspring

Options

A. both son and daughter are colour blind
B. all daughters are colour blind
C. all sons are normal
D. all sons are colour blind

Explanation

To solve the problem of a colorblind woman marrying a normal vision male and determining the potential offspring's vision status, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Genotypes**:
- The colorblind woman has the genotype **X^cX^c** (homozygous recessive) because colorblindness is a recessive trait.
- The normal vision male has the genotype **X^CY** (hemizygous, since males have one X and one Y chromosome).

2. **Determine the Gametes**:
- The colorblind woman can only produce gametes with the **X^c** allele.
- The normal vision male can produce two types of gametes: **X^C** and **Y**.

3. **Set Up the Punnett Square**:
- Create a Punnett square to visualize the potential offspring.
- The gametes from the mother (X^c) will be on one side and the gametes from the father (X^C and Y) will be on the other side.

| | X^C | Y |
|----------|-----------|-----------|
| **X^c** | X^CX^c | X^cY |
| **X^c** | X^CX^c | X^cY |

4. **Analyze the Offspring Genotypes**:
- From the Punnett square, we can see the possible genotypes of the offspring:
- **X^CX^c** (Daughter with normal vision, carrier)
- **X^cY** (Son with colorblindness)

5. **Determine the Phenotypes**:
- The daughters (X^CX^c) will have normal vision but will be carriers of the colorblind trait.
- The sons (X^cY) will be colorblind.

6. **Conclusion**:
- In this scenario, all daughters will be carriers of the colorblind trait (normal vision) and all sons will be colorblind.

### Final Answer:
- All daughters are carriers (normal vision), and all sons are colorblind.