A photosynthesising plant is releasing `.^(18)O` more than the normal. The plant must have been supplied with

Options

A. `O_(3)`
B. `H_(2)O` with `.^(18)O`
C. `CO_(2)` with `.^(18)O`
D. `C_(6)H_(12)O_(6)` with `.^(18)O`

Explanation

To solve the question regarding the photosynthesizing plant releasing more \(^{18}O\) than normal, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Photosynthesis**:
- Photosynthesis is the process where plants convert carbon dioxide and water into glucose and oxygen using sunlight. The overall reaction can be summarized as:
\[ 6CO_2 + 6H_2O \rightarrow C_6H_{12}O_6 + 6O_2 \]

2. **Identifying the Source of Oxygen**:
- In the photosynthesis equation, the oxygen released (O2) comes from the splitting of water (H2O) molecules, not from carbon dioxide (CO2). This is a crucial point.

3. **Analyzing the Isotope**:
- The question specifies that the plant is releasing \(^{18}O\), which is a radioactive isotope of oxygen. This indicates that the source of the oxygen being released must contain \(^{18}O\).

4. **Determining the Source of \(^{18}O\)**:
- Since the oxygen released during photosynthesis originates from water, if the plant is releasing \(^{18}O\), it means that the water it was supplied with must have contained \(^{18}O\).

5. **Conclusion**:
- Therefore, the plant must have been supplied with water (H2O) that contains \(^{18}O\). Other options like ozone (O3) or carbon dioxide (CO2) would not be correct because they do not contribute to the oxygen released during photosynthesis.

### Final Answer:
The plant must have been supplied with water (H2O) that contains \(^{18}O\).

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