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for a first -order reaction , the ha...

for a first -order reaction , the half - life period in independent of

A

zero

B

first

C

second

D

more than zero but less than first

Text Solution

Verified by Experts

The correct Answer is:
B
for a zero order reaction `t_(1//2)` is directly proportional to the intial concentration of the reactant `|R|_(0)`
`t_(1//2)prop|R|_(0) `
for a first order reaction
`k=(2303)/(t) log ""(|R|_(0))/(|R|)`
` at t_(1//2)|R|=(|R|_(0))/(2)`
so the above equation becomes
`K=(2303)/(t_(1//2))log""(|R|_(0))/([R]_(0)//2)`
`t_(1//2)=(2303)/(K)= log ""2= (2303)/(K)xx.3010`
`t_(1//2) = (.693)/(K)`
i.e., half life period is independent of initial concentration of a reactant .
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