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For the reaction N(2) to 3H(2) to 2NH(3)...

For the reaction `N_(2) to 3H_(2) to 2NH_(3)`, how are the rate of reaction expressions inter-related `(d[H_(2)])/(dt)` and `(d[NH_(3)])/(dt)`?

A

`3xx10^(-4) mol L^(-1)S^(-1)`

B

`4xx10^(-4) mol L^(-1)S^(-1)`

C

`6xx10^(-4) mol L^(-1)S^(-1)`

D

`1xx10^(-4) mol L^(-1)S^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
For the reaction ,
`N_(2)+3H_(2) to NH_(3)`
`rate =-(d[N_(2)])/(dt)=-(1)/(3)(d[H_(2)])/(dt)=+(1)/(2) (d[NH_(3)])/(dt)`
`or -(1)/(3)(d[H_(2)])/(dt)=+(d[NH_(3)])/(dty)`
`-(d[H_(2)])/(dt)=(3)/(2)xx2xx10^(-04)molL^(-1)S^(-1)`
`=3xx10^(-4)molL^(-1)S^(-1)`
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