The intermediates formed during the reaction of `R-overset(O)overset(||)C-NH_(2)` with `Br_(2)` and KOH are :

Options

A. RCONHBr and RNCO
B. RNHCOBr and RNCO
C. RNHBr and RCONHBr
D. `RCONBr_(2)`

Explanation

To solve the question regarding the intermediates formed during the reaction of the amide \( R-C(=O)-NH_2 \) with \( Br_2 \) and KOH, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reaction Type**:
The reaction in question is known as the Hofmann bromamide degradation reaction. This reaction involves the conversion of a primary amide into a primary amine with the loss of one carbon atom.

**Hint**: Recall that the Hofmann degradation specifically targets primary amides.

2. **Write the Structure of the Amide**:
The structure of the amide can be represented as \( R-C(=O)-NH_2 \).

**Hint**: Ensure you understand the functional groups present in the amide.

3. **Reaction with Bromine and KOH**:
When the amide \( R-C(=O)-NH_2 \) reacts with \( Br_2 \) in the presence of KOH, the bromine will react with the nitrogen atom of the amide.

**Hint**: Remember that KOH acts as a base and facilitates the reaction.

4. **Formation of the First Intermediate**:
The bromine will attach to the nitrogen, leading to the formation of the intermediate \( R-C(=O)-NBr \) (bromamide). Water is also produced in this step.

**Hint**: Look for the addition of bromine to the nitrogen atom.

5. **Elimination Reaction**:
The next step involves the elimination of potassium bromide (KBr) and the formation of a new intermediate \( R-C(=O)-N \) (an N-substituted amide).

**Hint**: Consider how the elimination of KBr occurs in the presence of KOH.

6. **Rearrangement**:
The intermediate undergoes a rearrangement where the nitrogen atom shifts to form a new bond with the alkyl group, resulting in the formation of \( R-N=C=O \) (isocyanate).

**Hint**: Rearrangement often involves shifting of groups to stabilize the molecule.

7. **Final Step - Hydrolysis**:
Finally, when this isocyanate reacts with water (from the KOH), it hydrolyzes to form the primary amine \( R-NH_2 \) and potassium carbonate \( K_2CO_3 \).

**Hint**: Hydrolysis is a common reaction for isocyanates.

8. **Identify the Intermediates**:
The two key intermediates formed during this reaction are:
- \( R-C(=O)-NBr \) (bromamide)
- \( R-N=C=O \) (isocyanate)

**Hint**: Make sure to list all intermediates that were formed throughout the reaction.

### Final Answer:
The intermediates formed during the reaction of \( R-C(=O)-NH_2 \) with \( Br_2 \) and KOH are:
1. \( R-C(=O)-NBr \)
2. \( R-N=C=O \)