When aniline reacts with oil of bitter almonds `(C_(6)H_(5)CHO)` condensation takes place and benzal derivative is formed This in knkown as .

Options

A. Millon's base
B. Schiff's reagent
C. Schiff's base
D. Benedict's reagent

Explanation

To solve the problem of what occurs when aniline reacts with oil of bitter almonds (benzaldehyde), we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Reactants**:
- The reactants in this reaction are aniline (C6H5NH2) and benzaldehyde (C6H5CHO).

2. **Understand the Reaction Type**:
- The reaction between aniline and benzaldehyde is a condensation reaction. In this type of reaction, two molecules combine with the loss of a small molecule, typically water.

3. **Draw the Structures**:
- Aniline has the structure:
```
NH2
|
C6H5
```
- Benzaldehyde has the structure:
```
O
||
C
|
C6H5
```

4. **Mechanism of the Reaction**:
- The nitrogen atom in the aniline has a lone pair of electrons, which can attack the carbonyl carbon of benzaldehyde. This forms a tetrahedral intermediate.
- As the reaction proceeds, a water molecule (H2O) is eliminated.

5. **Formation of the Product**:
- After the elimination of water, the product formed is known as benzyl aniline. The structure can be represented as:
```
C6H5
|
C
/ \
N H
```

6. **Identify the Type of Product**:
- The product, benzyl aniline, is classified as a Schiff's base. Schiff's bases are characterized by the presence of a C=N bond formed from the condensation of an amine and an aldehyde or ketone.

7. **Conclusion**:
- The reaction of aniline with benzaldehyde results in the formation of benzyl aniline, which is also known as a Schiff's base.

### Final Answer:
The reaction of aniline with oil of bitter almonds (benzaldehyde) results in the formation of a compound known as **Schiff's base**.