Of the following which is the product formed when cyclohexanone undergoes aldol condensation followed by heating?

Options

A.
B.
C.
D.

Explanation

To solve the problem of identifying the product formed when cyclohexanone undergoes aldol condensation followed by heating, we can follow these steps:

### Step 1: Identify the Structure of Cyclohexanone
Cyclohexanone is a cyclic ketone with the molecular formula C6H10O. The structure can be represented as follows:

```
O
||
C6H10
```

### Step 2: Check for Alpha Hydrogens
Cyclohexanone has alpha hydrogen atoms because it has carbons adjacent to the carbonyl group (C=O). The alpha carbons are the ones directly attached to the carbonyl carbon.

### Step 3: Aldol Condensation Reaction
In the presence of a dilute base (like NaOH), cyclohexanone can undergo aldol condensation. The base will abstract an alpha hydrogen, generating an enolate ion:

1. **Formation of Enolate Ion:**
- The base (OH-) abstracts an alpha hydrogen from cyclohexanone, resulting in the formation of an enolate ion.

2. **Nucleophilic Attack:**
- The enolate ion then attacks the carbonyl carbon of another cyclohexanone molecule, leading to the formation of a beta-hydroxy ketone.

### Step 4: Elimination of Water
The beta-hydroxy ketone formed can undergo dehydration (loss of water) upon heating, resulting in the formation of an alpha, beta-unsaturated carbonyl compound.

### Step 5: Final Product
The final product of the aldol condensation of cyclohexanone followed by heating is:

```
O
||
C6H10
\
C=C
```

This compound is an alpha, beta-unsaturated carbonyl compound.

### Conclusion
After analyzing the options provided in the question, the correct answer is option B, which corresponds to the product formed from the aldol condensation of cyclohexanone followed by heating.

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