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Acetone is treated with excess of ethano...

Acetone is treated with excess of ethanol in the presence of hydrochloric acid. The product obtained is

A

`CH_(3)CH_(2)CH_(2)-overset(O)overset(||)(C)-CH_(3)`

B

`CH_(3)CH_(2)CH_(2)-overset(O)overset(||)(C)-CH_(2)CH_(2)CH_(3)`

C

D

Text Solution

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The correct Answer is:
To solve the question regarding the treatment of acetone with excess ethanol in the presence of hydrochloric acid, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants in this reaction are acetone (a ketone) and ethanol (an alcohol). The chemical structure of acetone is \( CH_3COCH_3 \) and that of ethanol is \( C_2H_5OH \). 2. **Understanding the Reaction Conditions**: - The presence of hydrochloric acid (HCl) acts as a catalyst in this reaction, facilitating the formation of hemiacetals or hemiketals. 3. **Formation of Hemiketal**: - When acetone reacts with ethanol, the carbonyl group (C=O) of acetone reacts with the hydroxyl group (OH) of ethanol. This leads to the formation of a hemiketal. - The reaction can be represented as: \[ CH_3COCH_3 + C_2H_5OH \xrightarrow{HCl} CH_3C(OH)(C_2H_5)CH_3 \] - This product is known as a hemiketal because it contains one alkoxy group (from ethanol) and one hydroxyl group. 4. **Conversion to Ketal**: - Since the question states that there is an excess of ethanol, the hemiketal can further react with another molecule of ethanol. The hydroxyl group (OH) from the hemiketal is eliminated, and a new bond is formed with another ethanol molecule. - The reaction can be represented as: \[ CH_3C(OH)(C_2H_5)CH_3 + C_2H_5OH \rightarrow CH_3C(O C_2H_5)(O C_2H_5)CH_3 \] - The final product is a ketal, which is a fully substituted ether derived from the ketone. 5. **Final Product**: - The final product can be represented as: \[ CH_3C(O C_2H_5)(O C_2H_5)CH_3 \] - This compound is known as a ketal, specifically diethyl ketal of acetone. 6. **Conclusion**: - Therefore, the product obtained when acetone is treated with excess ethanol in the presence of hydrochloric acid is a ketal. ### Final Answer: The product obtained is **diethyl ketal of acetone**. ---
To solve the question regarding the treatment of acetone with excess ethanol in the presence of hydrochloric acid, we can follow these steps: ### Step-by-Step Solution: 1. **Identify the Reactants**: - The reactants in this reaction are acetone (a ketone) and ethanol (an alcohol). The chemical structure of acetone is \( CH_3COCH_3 \) and that of ethanol is \( C_2H_5OH \). 2. **Understanding the Reaction Conditions**: ...
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