Which of the following on treatment with aqueus sodium hydroxide will give corresponding alcohol and acid?

Options

A. `C_(6)H_(5)CH_(2)CHO`
B. `C_(6)H_(5)CHO`
C. `CH_(3)CH_(2)CH_(2)CHO`
D. `CH-overset(O)overset(|)(C)-CH_(3)`

Explanation

To solve the question, we need to identify which compound, when treated with aqueous sodium hydroxide, will undergo the Cannizzaro reaction to produce an alcohol and a carboxylic acid. The Cannizzaro reaction occurs with aldehydes that do not have alpha-hydrogens.

### Step-by-Step Solution:

1. **Identify the Compounds**: We need to analyze the given compounds to check for the presence of alpha-hydrogens. The compounds provided are:
- (a) C6H5CH2CHO (Benzaldehyde)
- (b) C6H5CHO (Benzaldehyde)
- (c) C6H5C(OH)CH3 (an alcohol)
- (d) C6H5C(O)CH3 (an acetophenone)

2. **Check for Alpha-Hydrogens**:
- **Compound (a)**: C6H5CH2CHO has alpha-hydrogens (the CH2 group has hydrogens). Therefore, it cannot undergo the Cannizzaro reaction.
- **Compound (b)**: C6H5CHO (Benzaldehyde) does not have any alpha-hydrogens. Thus, it is a candidate for the Cannizzaro reaction.
- **Compound (c)**: C6H5C(OH)CH3 is an alcohol and does not have the aldehyde functional group, so it is not applicable for the Cannizzaro reaction.
- **Compound (d)**: C6H5C(O)CH3 (acetophenone) has alpha-hydrogens and will not undergo the Cannizzaro reaction.

3. **Determine the Reaction for Compound (b)**:
- When benzaldehyde (C6H5CHO) is treated with aqueous sodium hydroxide, it undergoes the Cannizzaro reaction.
- In this reaction, one molecule of benzaldehyde is oxidized to form sodium benzoate (C6H5COONa), and another molecule is reduced to form benzyl alcohol (C6H5CH2OH).

4. **Write the Products**:
- The products formed from the Cannizzaro reaction of benzaldehyde are:
- **Benzyl Alcohol**: C6H5CH2OH
- **Sodium Benzoate**: C6H5COONa

5. **Conclusion**: The compound that undergoes the Cannizzaro reaction to give the corresponding alcohol and acid is **option (b) C6H5CHO (Benzaldehyde)**.

### Final Answer:
The correct answer is **option (b)**.