Reduction of aldehydes and ketones into hydrocarbons using hydrazine and sodium ethoxide is called :

Options

A. Clemmensen reduction
B. Cope reduction
C. Dow reduction
D. Wolff-Kishner reduction

Explanation

To solve the question regarding the reduction of aldehydes and ketones into hydrocarbons using hydrazine and sodium ethoxide, we need to identify the name of the reaction involved. The answer is as follows:

### Step-by-Step Solution:

1. **Identify the Reactants**: The reactants in this reduction process are aldehydes or ketones and hydrazine (N2H4) in the presence of a base such as sodium ethoxide (NaOEt) or potassium hydroxide (KOH).

2. **Understanding the Reaction**: The reaction involves the conversion of the carbonyl group (C=O) present in aldehydes and ketones into a hydrocarbon. This is achieved through a two-step process:
- First, the hydrazine reacts with the carbonyl compound to form a hydrazone intermediate.
- Second, the hydrazone undergoes elimination of nitrogen gas (N2) to yield the corresponding hydrocarbon.

3. **Naming the Reaction**: This specific reduction process using hydrazine is known as the **Wolf-Krishner Reduction**. It is named after the chemists who developed the method.

4. **Conclusion**: Therefore, the reduction of aldehydes and ketones into hydrocarbons using hydrazine and sodium ethoxide is referred to as the **Wolf-Krishner Reduction**.

### Final Answer:
The reduction of aldehydes and ketones into hydrocarbons using hydrazine and sodium ethoxide is called the **Wolf-Krishner Reduction**.

---