In this reaction,
`CH_(3)CHOtoCH_(3)CH(OH)Cnoverset(H*OH)toCH_(3)CH(OH)COOH`
An asymmetric centre is generated. The acid obtained would be

Options

A. 50%D+50% L-isomer
B. 20%D+80% L-isomer
C. D-isomer
D. L-isomer

Explanation

To solve the problem, we need to analyze the reaction step by step and identify the final product formed, which is an acid.

### Step-by-Step Solution:

1. **Identify the Starting Material**:
The reaction starts with an aldehyde, specifically acetaldehyde (CH₃CHO).

2. **Reaction with HCN**:
The acetaldehyde undergoes a reaction with hydrogen cyanide (HCN). This reaction leads to the formation of a cyanohydrin. The reaction can be represented as:
\[ CH₃CHO + HCN \rightarrow CH₃C(OH)(CN)H \]
Here, the cyanide (CN) group adds to the carbonyl carbon, and a hydroxyl (OH) group is also attached.

3. **Formation of an Asymmetric Center**:
The product formed (CH₃C(OH)(CN)H) has a chiral center because it has four different groups attached to the carbon atom that bears the hydroxyl group (OH). This results in the formation of two enantiomers: D-isomer and L-isomer.

4. **Hydrolysis of the Cyanohydrin**:
The next step involves hydrolysis of the cyanohydrin. When the cyanohydrin is hydrolyzed, the cyanide group (CN) is converted into a carboxylic acid (COOH). The reaction can be represented as:
\[ CH₃C(OH)(CN)H + H₂O \rightarrow CH₃C(OH)COOH \]
The product formed here is lactic acid (CH₃C(OH)COOH).

5. **Final Product**:
The final product of the reaction is lactic acid, which exists as a racemic mixture of D-lactic acid and L-lactic acid. This means that there are equal amounts (50% each) of the two enantiomers.

### Conclusion:
The acid obtained from the reaction is **lactic acid (CH₃C(OH)COOH)**.