`underset((A))(3CH_(3)COCH_(3))underset(-H_(2)O)overset(HCl)to(CH_(3))_(2)C=CH-underset((B))(CO)-CH=C(CH_(3))_(2)`.
This polymer (B) is obtained when acetone is saturated with HCl gas, B can be

Options

A. Phorone
B. Formose
C. Diacetone alcohol
D. Mesityl oxide

Explanation

To solve the problem, we need to understand the reaction of acetone (3CH₃COCH₃) when it is saturated with HCl gas. The process involves the self-condensation of acetone, leading to the formation of a polymeric compound. Let's break down the steps:

### Step-by-Step Solution

1. **Identify the Reactant**:
The reactant is acetone, which has the formula CH₃COCH₃. We have three moles of acetone.

2. **Write the Reaction**:
When acetone is treated with HCl, a condensation reaction occurs. The reaction can be represented as:
\[ 3 \text{CH}_3\text{COCH}_3 \xrightarrow{\text{HCl}} \text{B} + 2 \text{H}_2\text{O} \]

3. **Condensation Reaction**:
In the presence of HCl, two molecules of water are eliminated. The carbonyl groups (C=O) of the acetone molecules will react, leading to the formation of new double bonds and a polymeric structure.

4. **Formation of Product B**:
The product formed after the elimination of water will have a structure where the acetone units are linked together. The resulting structure can be represented as:
\[ \text{(CH}_3)_2\text{C=CH-CO-CH=C(CH}_3)_2 \]
This structure indicates that we have a conjugated system with double bonds and carbonyl groups.

5. **Naming the Product**:
The product formed is known as "Foron". It is a self-condensation product of acetone and is combustible in nature when exposed to heat or flame.

6. **Final Answer**:
Therefore, the polymer (B) obtained from the reaction of acetone saturated with HCl is **Foron**.