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Which of the following pairs of compound...

Which of the following pairs of compound is isoelectronic and isostructure ?

A

`BeCl_(2),XeF_(2)`

B

`Tel_(2), XeF_(2)`

C

`Ibr_(2)^(-), XeF_(2)`

D

`IF_(3), XeF_(2)`

Text Solution

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The correct Answer is:
To determine which of the given pairs of compounds are isoelectronic and isostructural, we need to follow these steps: ### Step 1: Understand Isoelectronic and Isostructural - **Isoelectronic**: Compounds or ions that have the same number of total valence electrons. - **Isostructural**: Compounds or ions that have the same geometry or structure. ### Step 2: Identify the Valence Electrons We need to calculate the total number of valence electrons for each compound. 1. **BeCl2 (Beryllium Chloride)**: - Beryllium (Be) has 2 valence electrons. - Chlorine (Cl) has 7 valence electrons, and there are 2 Cl atoms. - Total = 2 (Be) + 2 × 7 (Cl) = 2 + 14 = **16 valence electrons**. 2. **XeF2 (Xenon Difluoride)**: - Xenon (Xe) has 8 valence electrons. - Fluorine (F) has 7 valence electrons, and there are 2 F atoms. - Total = 8 (Xe) + 2 × 7 (F) = 8 + 14 = **22 valence electrons**. 3. **TeI2 (Tellurium Iodide)**: - Tellurium (Te) has 6 valence electrons. - Iodine (I) has 7 valence electrons, and there are 2 I atoms. - Total = 6 (Te) + 2 × 7 (I) = 6 + 14 = **20 valence electrons**. 4. **IBr2- (Iodine Bromide Ion)**: - Iodine (I) has 7 valence electrons. - Bromine (Br) has 7 valence electrons, and there are 2 Br atoms. - The negative charge (-1) indicates one extra electron. - Total = 7 (I) + 2 × 7 (Br) + 1 = 7 + 14 + 1 = **22 valence electrons**. 5. **IF3 (Iodine Trifluoride)**: - Iodine (I) has 7 valence electrons. - Fluorine (F) has 7 valence electrons, and there are 3 F atoms. - Total = 7 (I) + 3 × 7 (F) = 7 + 21 = **28 valence electrons**. ### Step 3: Compare Valence Electrons Now we compare the total number of valence electrons for each compound: - BeCl2: 16 - XeF2: 22 - TeI2: 20 - IBr2-: 22 - IF3: 28 ### Step 4: Identify Isoelectronic Pairs From the calculations: - **IBr2-** and **XeF2** both have **22 valence electrons**. Hence, they are isoelectronic. ### Step 5: Check for Isostructural Pairs Now we need to check the geometry: - **IBr2-**: Linear structure (due to 2 bonding pairs and 3 lone pairs). - **XeF2**: Also has a linear structure (due to 3 lone pairs and 2 bonding pairs). ### Conclusion The pair of compounds that are both isoelectronic and isostructural is **IBr2- and XeF2**. ---

To determine which of the given pairs of compounds are isoelectronic and isostructural, we need to follow these steps: ### Step 1: Understand Isoelectronic and Isostructural - **Isoelectronic**: Compounds or ions that have the same number of total valence electrons. - **Isostructural**: Compounds or ions that have the same geometry or structure. ### Step 2: Identify the Valence Electrons We need to calculate the total number of valence electrons for each compound. ...
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