Which of the statements given below is incorrect ?

Options

A. `Cl_(2)O_(7)` is an anhydride of perchloric acid
B. `O_(3)` molecule is bent
C. `ONF` is isoelectronic with `NO_(2)`
D. `OF_(2)` is an oxide of florine

Explanation

To determine which of the statements given is incorrect, we will evaluate each option one by one.

### Step 1: Evaluate Statement A
**Statement A:** Cl2O7 is an anhydride of perchloric acid (HClO4).

- **Analysis:**
- The formula for perchloric acid is HClO4.
- An anhydride of an acid is formed by removing water (H2O) from the acid.
- If we take two moles of HClO4 and remove one water molecule (H2O), we get:
\[ 2 \text{HClO4} - \text{H2O} \rightarrow \text{Cl2O7} \]
- This confirms that Cl2O7 is indeed the anhydride of perchloric acid.

**Conclusion:** Statement A is correct.

### Step 2: Evaluate Statement B
**Statement B:** O3 (ozone) has a bent structure.

- **Analysis:**
- The molecular structure of ozone (O3) consists of one central oxygen atom bonded to two other oxygen atoms.
- Due to the presence of a lone pair of electrons on the central oxygen, the molecule adopts a bent shape.
- The bond angle is approximately 117 degrees, confirming that ozone is indeed a bent molecule.

**Conclusion:** Statement B is correct.

### Step 3: Evaluate Statement C
**Statement C:** ONF is isoelectronic with NO2.

- **Analysis:**
- To check if ONF (Oxygen, Nitrogen, Fluorine) is isoelectronic with NO2 (Nitrogen Dioxide), we need to count the total number of electrons.
- For NO2:
- Nitrogen (N) has 7 electrons.
- Each Oxygen (O) has 8 electrons, and there are 2 Oxygens.
- NO2 has a total of \(7 + 8 + 8 + 1 = 24\) electrons (considering the negative charge).
- For ONF:
- Oxygen (O) has 8 electrons.
- Nitrogen (N) has 7 electrons.
- Fluorine (F) has 9 electrons.
- Thus, ONF has a total of \(8 + 7 + 9 = 24\) electrons.
- Since both species have the same number of electrons, they are isoelectronic.

**Conclusion:** Statement C is correct.

### Step 4: Evaluate Statement D
**Statement D:** OF2 is an oxide of fluorine.

- **Analysis:**
- OF2 consists of one oxygen atom and two fluorine atoms.
- The electronegativity of fluorine is greater than that of oxygen.
- Therefore, in OF2, oxygen behaves as a less electronegative atom, making it a fluoride of oxygen rather than an oxide of fluorine.
- The correct nomenclature for OF2 is "fluoride of oxygen," not "oxide of fluorine."

**Conclusion:** Statement D is incorrect.

### Final Answer
The incorrect statement is **D: OF2 is an oxide of fluorine.**

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