Home
Class 12
CHEMISTRY
The oxidation state of sulphur in the a...

The oxidation state of sulphur in the anions `SO_(3)^(-2),SO_(4)^(2-),S_(2)O_(4)^(2-),S_(2)O_(6)^(2-)` is in the order of

A

`S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-) lt SO_(3)^(2-)`

B

`S_(2)O_(6)^(2-) lt S_(2)O_(4)^(2-) lt SO_(3)^(2-)`

C

`S_(2)O_(4)^(2-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`

D

`SO_(3)^(2-) lt S_(2)O_(4)^(2-) lt S_(2)O_(6)^(2-)`

Text Solution

Verified by Experts

The correct Answer is:
C
Oxidation state of S in `SO_(3)^(2-)`
`x + (-2 xx 3) = - 2`,
`x = +6-2=+4`
Oxidation state of `S` in `S_(2)O_(4)^(2-)`.
`2x+(-2xx4) = -2`
`2x=+8-2=+6`
`x = (+6)/(2) = +3`
Oxidation state of S in `S_(2)O_(6)^(2-)`
`2x + (-2xx6) = -2`
`2x = +12-2 =10`
`x = 10/2 = +5`
Hence, increasing order of oxidation states of S is
`S_(2)O_(4)^(3-) lt SO_(3)^(2-) lt S_(2)O_(6)^(2-)`.
Promotional Banner

Similar Questions

Explore conceptually related problems

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

The oxidation states of sulphur in the anions SO_(3)^(2-), S_(2)O_(4)^(2-) , and S_(2)O_(6)^(2-) follow the order

I_(2)+S_(2)O_(3)^(2-) to I^(-)+S_(4)O_(6)^(2-)

I_(2)+S_(2)O_(3)^(2-) to I^(-)+S_(4)O_(6)^(2-)

Find the oxidation number of sulphur in the following compounds: H_(2)S,H_(2)SO_(4),S_(2)O_(4)^(2-),S_(2)O_(8)^(2-),HSO_(3)^(ө) .

The oxidation state of sulphur in sodium tetrathionate ( Na_(2)S_(4)O_(6) ) is :

The average oxidation state of sulphur atom in S_4O_6^(2-) ion is

The oxidation number of sulphur in H_(2)S_(2)O_(8) is: