Home
Class 12
CHEMISTRY
Number of electrons shared in the form...

Number of electrons shared in the formation of nitrogen molecules is

A

6

B

10

C

2

D

8

Text Solution

AI Generated Solution

The correct Answer is:
To determine the number of electrons shared in the formation of nitrogen molecules (N₂), we can follow these steps: ### Step 1: Understand the Electron Configuration The electron configuration of a nitrogen atom is \(1s^2 2s^2 2p^3\). Since a nitrogen molecule consists of two nitrogen atoms, we will consider the combined electron configuration for N₂, which will be \(1s^2 2s^2 2p^6\). ### Step 2: Draw the Molecular Orbital Diagram In the molecular orbital theory (MOT), we fill the molecular orbitals based on the energy levels. The order of filling for N₂ is: - \( \sigma_{1s} \) (2 electrons) - \( \sigma^*_{1s} \) (0 electrons) - \( \sigma_{2s} \) (2 electrons) - \( \sigma^*_{2s} \) (0 electrons) - \( \sigma_{2p_z} \) (2 electrons) - \( \pi_{2p_x} \) (2 electrons) - \( \pi_{2p_y} \) (2 electrons) - \( \pi^*_{2p_x} \) (0 electrons) - \( \pi^*_{2p_y} \) (0 electrons) - \( \sigma^*_{2p_z} \) (0 electrons) ### Step 3: Count the Bonding and Antibonding Electrons - **Bonding Electrons**: - \( \sigma_{1s} \): 2 - \( \sigma_{2s} \): 2 - \( \sigma_{2p_z} \): 2 - \( \pi_{2p_x} \): 2 - \( \pi_{2p_y} \): 2 - **Total Bonding Electrons** = \( 2 + 2 + 2 + 2 + 2 = 10 \) - **Antibonding Electrons**: - \( \sigma^*_{1s} \): 0 - \( \sigma^*_{2s} \): 0 - \( \sigma^*_{2p_z} \): 0 - \( \pi^*_{2p_x} \): 0 - \( \pi^*_{2p_y} \): 0 - **Total Antibonding Electrons** = \( 0 + 0 + 0 + 0 + 0 = 0 \) ### Step 4: Calculate the Bond Order The bond order is calculated using the formula: \[ \text{Bond Order} = \frac{(\text{Number of Bonding Electrons} - \text{Number of Antibonding Electrons})}{2} \] Substituting the values: \[ \text{Bond Order} = \frac{(10 - 0)}{2} = 5 \] ### Step 5: Determine the Number of Electrons Shared Each bond consists of 2 electrons. Since the bond order is 3, the total number of electrons shared in the formation of the nitrogen molecule is: \[ \text{Total Electrons Shared} = \text{Bond Order} \times 2 = 3 \times 2 = 6 \] ### Final Answer The number of electrons shared in the formation of nitrogen molecules is **6**. ---

To determine the number of electrons shared in the formation of nitrogen molecules (N₂), we can follow these steps: ### Step 1: Understand the Electron Configuration The electron configuration of a nitrogen atom is \(1s^2 2s^2 2p^3\). Since a nitrogen molecule consists of two nitrogen atoms, we will consider the combined electron configuration for N₂, which will be \(1s^2 2s^2 2p^6\). ### Step 2: Draw the Molecular Orbital Diagram In the molecular orbital theory (MOT), we fill the molecular orbitals based on the energy levels. The order of filling for N₂ is: - \( \sigma_{1s} \) (2 electrons) ...
Promotional Banner

Similar Questions

Explore conceptually related problems

The bond in the formation of fluorine molecule will be

Explain the formation of CaF_2 molecule.

The electronic configuration of nitrogen is 2,5. How many electrons in the outer shell of a nitrogen atom are not involved in the formation of a nitrogen molecule ?

The electronic configuration of nitrogen is 2, 5. How many elelctrons in the outer shell nitrogen atom are not involved in the formation of a nitrogen molecule.

Explain the formation of C_2 H_2 molecule.

The number of lone pair of electrons on each atom of oxygen molecule is

Find the average speed of nitrogen molecules at 25^(@)C.

There are …………. pi bonds in a nitrogen molecule

Find the number of ATP required in the reduction step of the C3 cycle if the cycle is involved in the formation of one sucrose molecule.

In the formation of electrovalent compounds, electrons are transferred from one element to another. How are electrons involved in the formation of a covalent compound ?