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The equations of two waves given as x = ...

The equations of two waves given as `x = a cos (omega t = delta)` and `y = a cos (omega t + alpha)`, where `delta = alpha + pi/2`, then resultant wave represent:

A

a circle (c.w)

B

A circle (a.c.w)

C

an Ellipse (c.w)

D

an ellipse (a.c.w)

Text Solution

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The correct Answer is:
To solve the problem, we need to analyze the equations of the two waves given as: 1. \( x = A \cos(\omega t + \delta) \) 2. \( y = A \cos(\omega t + \alpha) \) where \( \delta = \alpha + \frac{\pi}{2} \). ### Step-by-step Solution: **Step 1: Substitute the value of \( \delta \)** From the problem, we know that: \[ \delta = \alpha + \frac{\pi}{2} \] Substituting this into the equation for \( x \): \[ x = A \cos(\omega t + \alpha + \frac{\pi}{2}) \] **Step 2: Simplify the equation for \( x \)** Using the trigonometric identity \( \cos(\theta + \frac{\pi}{2}) = -\sin(\theta) \), we can rewrite \( x \): \[ x = A \cos(\omega t + \alpha + \frac{\pi}{2}) = -A \sin(\omega t + \alpha) \] **Step 3: Write the equations for both waves** Now we have: 1. \( x = -A \sin(\omega t + \alpha) \) 2. \( y = A \cos(\omega t + \alpha) \) **Step 4: Square both equations and add them** To find the resultant wave, we square both equations: \[ x^2 = A^2 \sin^2(\omega t + \alpha) \] \[ y^2 = A^2 \cos^2(\omega t + \alpha) \] Adding these two equations: \[ x^2 + y^2 = A^2 \sin^2(\omega t + \alpha) + A^2 \cos^2(\omega t + \alpha) \] **Step 5: Use the Pythagorean identity** Using the identity \( \sin^2(\theta) + \cos^2(\theta) = 1 \): \[ x^2 + y^2 = A^2(1) = A^2 \] **Step 6: Identify the shape of the resultant wave** The equation \( x^2 + y^2 = A^2 \) represents a circle of radius \( A \). **Step 7: Determine the direction of the wave** To determine the direction (clockwise or anticlockwise), we analyze the parametric equations: - For \( x = -A \sin(\omega t + \alpha) \) - For \( y = A \cos(\omega t + \alpha) \) As \( \omega t \) increases, \( \sin(\omega t + \alpha) \) increases from 0 to 1, causing \( x \) to go from 0 to -A, while \( y \) goes from A to 0. This indicates that the motion is in the anticlockwise direction. ### Final Answer: The resultant wave represents a circle in the anticlockwise direction. ---
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