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When an electron do transition from n = ...

When an electron do transition from n = 4 to n = 2, then emitted line in spectrum will be:

A

First line of Lyman-series

B

Second lien of Balmer

C

First line of pashen series

D

Second lien of paschen series

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To solve the problem of determining the emitted line in the spectrum when an electron transitions from n = 4 to n = 2, we can follow these steps: ### Step-by-Step Solution: 1. **Understand the Transition**: The electron is transitioning from a higher energy level (n = 4) to a lower energy level (n = 2). In hydrogen-like atoms, these transitions result in the emission of photons, which correspond to specific wavelengths in the spectrum. 2. **Identify the Series**: The transition from n = 4 to n = 2 falls within the Balmer series. The Balmer series is characterized by transitions that end at n = 2 and involves higher energy levels (n = 3, 4, 5, ...). 3. **Determine the Specific Transition**: In the Balmer series: - The transition from n = 3 to n = 2 corresponds to the first line (H-alpha). - The transition from n = 4 to n = 2 corresponds to the second line of the Balmer series. 4. **Conclusion**: Therefore, the emitted line in the spectrum when an electron transitions from n = 4 to n = 2 is the second line of the Balmer series. ### Final Answer: The emitted line in the spectrum will be the second line of the Balmer series. ---
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