Polarization of electrons in acrolein may be written as:

Options

A. `overset(+delta)(CH_(2)) = CH - overset(- delta)(CHO)`
B. `overset(- delta)(CH_(2)) = CH - overset(+delta)(CHO)`
C. `overset(-delta)(CH_(2)) = CH - overset(+ delta)(CHO)`
D. `overset(+delta)(CH_(2)) = CH - overset(- delta)(CHO)`

Answer

To solve the question regarding the polarization of electrons in acrolein, we will follow these steps:

### Step 1: Write the Molecular Structure of Acrolein
Acrolein has the molecular formula C3H4O. Its structure can be represented as:
\[ \text{CH}_2= \text{CH}-\text{C}(= \text{O})-\text{H} \]
This shows that acrolein contains a double bond between the first two carbon atoms and a carbonyl group (C=O) at the end.

### Step 2: Identify the Electronegativity of Atoms
In acrolein, the oxygen atom is more electronegative than carbon. This means that oxygen will attract the shared electrons in the C=O bond more strongly than carbon.

### Step 3: Analyze Electron Distribution
Due to the difference in electronegativity, the electrons in the C=O bond will be pulled towards the oxygen atom. This results in the oxygen gaining a partial negative charge (δ-) and the carbon atom (to which it is bonded) gaining a partial positive charge (δ+).

### Step 4: Delocalization of Electrons
To stabilize the positive charge on the carbon, the pi electrons from the double bond (C=C) can shift towards the positively charged carbon. This delocalization helps in stabilizing the molecule.

### Step 5: Final Representation of Polarization
After the delocalization, the structure can be represented as:
\[ \text{CH}_2^{+} - \text{CH} - \text{O}^{-} \]
This shows that the carbon adjacent to the oxygen now has a partial positive charge, while the oxygen carries a partial negative charge.

### Conclusion
The polarization of electrons in acrolein can be summarized with the following charges:
- The carbon atom bonded to the oxygen has a partial positive charge (δ+).
- The oxygen atom has a partial negative charge (δ-).