Which of the following reagents convert the propene to `1`-propanol?

Options

A. `H_(2)O, H_(2) SO_(4)`
B. `B_(2)H_(6), H_(2) O, OH^(-)`
C. `Hg(Oac)_(2), NaBH_(4)//H_(2)O`
D. `Aq.KOH`

Answer

To convert propene (CH3CH=CH2) to 1-propanol (CH3CH2CH2OH), we can use diborane (B2H6) followed by oxidation. Here’s a step-by-step solution:

### Step 1: Identify the starting material
The starting material is propene, which has the structure CH3-CH=CH2.

### Step 2: React propene with diborane (B2H6)
When propene reacts with diborane, the boron atom interacts with the double bond of propene. The reaction can be represented as:
- Propene + B2H6 → (CH3-CH2-CH2)B(OH)2

### Step 3: Formation of trialkylborane
In this step, diborane adds across the double bond of propene, forming a trialkylborane. The boron atom bonds to the less substituted carbon atom (the terminal carbon), leading to the formation of:
- CH3-CH2-CH2-BH2

### Step 4: Oxidation of trialkylborane
Next, we oxidize the trialkylborane using hydrogen peroxide (H2O2) in the presence of a base (usually NaOH). This step converts the boron compound into an alcohol:
- (CH3-CH2-CH2)B(OH)2 + H2O2 → CH3-CH2-CH2OH + B(OH)3

### Step 5: Final product
The final product of this reaction is 1-propanol (CH3-CH2-CH2OH), which is a primary alcohol.

### Conclusion
The reagent that converts propene to 1-propanol is diborane (B2H6) followed by oxidation with hydrogen peroxide (H2O2).

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