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The conjugate acid of overset(Theta)NH(2...

The conjugate acid of `overset(Theta)NH_(2)` is

A

`NH_(4) OH`

B

`NH_(4)^(+)`

C

`NH^(-2)`

D

`NH_(3)`

Text Solution

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The correct Answer is:
To find the conjugate acid of the amide ion (NH₂⁻), we need to follow these steps: ### Step 1: Understand the concept of conjugate acids and bases A conjugate acid is formed when a base gains a proton (H⁺). In this case, the base we are considering is the amide ion (NH₂⁻). **Hint:** Remember that the conjugate acid is formed by adding a proton to the base. ### Step 2: Identify the base The base given in the question is the amide ion, which is represented as NH₂⁻. **Hint:** Recognize that NH₂⁻ is a negatively charged ion, indicating it can accept a proton. ### Step 3: Add a proton to the base When we add a proton (H⁺) to the amide ion (NH₂⁻), we perform the following reaction: \[ \text{NH}_2^- + \text{H}^+ \rightarrow \text{NH}_3 \] **Hint:** The addition of a proton changes the charge and the structure of the ion. ### Step 4: Determine the product The product of this reaction is ammonia (NH₃). Thus, the conjugate acid of the amide ion (NH₂⁻) is ammonia (NH₃). **Hint:** Check if the resulting compound is neutral; ammonia has no charge. ### Conclusion The conjugate acid of NH₂⁻ is NH₃ (ammonia). **Final Answer:** NH₃
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