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For the disproportion of copper: 2 Cu^...

For the disproportion of copper:
`2 Cu^(+) to Cu^(+2) + Cu E^(0)` is :- Given `E^(0)` for `Cu^(+2)//Cu` is 0.34 V & `E^(0)` for `Cu^(+2)//Cu^(+)` is 0.15 V:

A

0.49 V

B

`-0.19V`

C

0.38 V

D

`-0.38 V`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem of calculating the standard electrode potential (E°) for the disproportionation of copper, we need to analyze the given half-reactions and their respective standard electrode potentials. ### Step-by-Step Solution: 1. **Identify the Half-Reactions**: The disproportionation reaction given is: \[ 2 \text{Cu}^+ \rightarrow \text{Cu}^{2+} + \text{Cu} \] We can break this down into two half-reactions: - Half-reaction 1: \(\text{Cu}^{2+} + 2e^- \rightarrow 2\text{Cu}\) with \(E^\circ = +0.34 \, \text{V}\) - Half-reaction 2: \(\text{Cu}^+ + e^- \rightarrow \text{Cu}\) with \(E^\circ = ?\) (we will calculate this) 2. **Use Given Values**: We know: - \(E^\circ\) for \(\text{Cu}^{2+} + e^- \rightarrow \text{Cu}^+\) is \(0.15 \, \text{V}\). - We need to find \(E^\circ\) for the half-reaction \(\text{Cu}^+ + e^- \rightarrow \text{Cu}\). 3. **Calculate \(E^\circ\) for \(\text{Cu}^+ + e^- \rightarrow \text{Cu}\)**: Using the relationship: \[ \Delta G^\circ = -nFE^\circ \] For the reaction \(\text{Cu}^{2+} + 2e^- \rightarrow 2\text{Cu}\): \[ \Delta G^\circ = -2F \cdot 0.34 \] For the reaction \(\text{Cu}^{2+} + e^- \rightarrow \text{Cu}^+\): \[ \Delta G^\circ = -F \cdot 0.15 \] We can relate these two: \[ -2F \cdot 0.34 = -F \cdot 0.15 + -F \cdot E^\circ \] Simplifying gives: \[ 2 \cdot 0.34 = 0.15 + E^\circ \] \[ 0.68 - 0.15 = E^\circ \] \[ E^\circ = 0.53 \, \text{V} \] 4. **Combine the Half-Reactions**: Now, we have: - Half-reaction 1 (reversed): \(\text{Cu}^+ \rightarrow \text{Cu}^{2+} + e^-\) with \(E^\circ = -0.15 \, \text{V}\) - Half-reaction 2: \(\text{Cu}^+ + e^- \rightarrow \text{Cu}\) with \(E^\circ = 0.53 \, \text{V}\) 5. **Calculate the Overall E° for the Disproportionation Reaction**: Now we can add the potentials: \[ E^\circ_{\text{total}} = (-0.15) + (0.53) = 0.38 \, \text{V} \] ### Final Answer: The standard electrode potential (E°) for the disproportionation of copper is: \[ \boxed{0.38 \, \text{V}} \]
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