Home
Class 12
PHYSICS
A black body has maximum wavelength lamb...

A black body has maximum wavelength `lambda_(m)` at temperature `2000 K`. Its corresponding wavelength at temperature 3000 will be

A

`3/2lambda_m`

B

`2/3lambda_m`

C

`16/81lambda_m`

D

`81/16lambda_m`

Text Solution

Verified by Experts

The correct Answer is:
B
Promotional Banner

Similar Questions

Explore conceptually related problems

A black body emits maximum radiation of wavelength lambda_(1) at a certain temperature T_(1) . On increasing the temperature, the total energy of radiation emitted is increased 16 times at temperature T_(2) . If lambda_(2) is the wavelength corresponding to which maximum radiation is emitted at temperature T_(2) . Calculate the value of ((lambda_(1))/(lambda_(2))) .

A black body emits radiation at the rate P when its temperature is T. At this temperature the wavelength at which the radiation has maximum intensity is lamda_0 , If at another temperature T' the power radiated is P' and wavelength at maximum intensity is (lamda_0)/(2) then

A black body emits radiation at the rate P when its temperature is T. At this temperature the wavelength at which the radiation has maximum intensity is lamda_0 , If at another temperature T' the power radiated is P' and wavelength at maximum intensity is (lamda_0)/(2) then

A black body with surface area 0.001 m^(2) is heated upto a temperature 400 K and is suspended in a room temperature 300K. The intitial rate of loss of heat from the body to room is

Temperature of black body is 3000K . When black body cools, then change in wevelength Deltalambda = 9 micron corresponding to maximum energy density. Now temperature of black body is :-

De Broglie wavelength lambda associated with neutrons is related with absolute temperature T as

A black body is at a temperature 300 K . It emits energy at a rate, which is proportional to

A black body at 1373 ^@C emits maximum energy corresponding to a wavelength of 1.78 microns. The temperature of the moon for which lamda_m=14 micron wood be

The power radiated by a black body is P, and it radiates maximum energy around the wavelength lambda_(0) . If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength 3lambda_(0)//4 , the power radiated by it will increase by a factor of

The power radiated by a black body is P, and it radiates maximum energy around the wavelength lambda_(0) . If the temperature of the black body is now changed so that it radiates maximum energy around a wavelength 3lambda_(0)//4 , the power radiated by it will increase by a factor of