Which alkene on ozonolysis gives `CH_(3)CH_(2)CHO` and `CH_(3)underset(O)underset(||)(C )CH_(3)` ?

Options

A.
B. `CH_3CH_2CH=CHCH_2CH_3`
C. `CH_3CH_2CH_2=CHCH_3`
D. `CH_3-undersetunderset(CH_3)|C=CHCH_3`

Answer

To solve the problem of identifying the alkene that gives the products CH₃CH₂CHO (which is butanal) and CH₃C(=O)CH₃ (which is acetone) upon ozonolysis, we can follow these steps:

### Step 1: Understand the Products
The products of ozonolysis are:
- CH₃CH₂CHO (butanal)
- CH₃C(=O)CH₃ (acetone)

### Step 2: Analyze the Structure of the Products
1. **Butanal (CH₃CH₂CHO)** indicates that there is a terminal carbonyl group (aldehyde) at the end of a four-carbon chain.
2. **Acetone (CH₃C(=O)CH₃)** indicates a ketone with a three-carbon chain where the carbonyl group is between two methyl groups.

### Step 3: Determine the Alkene Structure
To find the alkene that can produce these two products upon ozonolysis, we need to think about how ozonolysis works:
- Ozonolysis cleaves the double bond of an alkene and forms carbonyl compounds.

### Step 4: Construct the Alkene
To yield both products, we can consider the following alkene:
- The alkene must have a double bond between a carbon that can lead to butanal and a carbon that can lead to acetone.

One possible alkene that fits this description is **2-pentene** (CH₃CH=CHCH₂CH₃).

### Step 5: Ozonolysis of 2-Pentene
When 2-pentene undergoes ozonolysis:
- The double bond between the second and third carbon atoms breaks.
- The resulting fragments are:
- From the left side: CH₃CH₂CHO (butanal)
- From the right side: CH₃C(=O)CH₃ (acetone)

### Conclusion
Thus, the alkene that gives CH₃CH₂CHO and CH₃C(=O)CH₃ upon ozonolysis is **2-pentene**.

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