Which of following is correct : -

Options

A. Any aldehyde gives secondary alcohol on reduction
B. Reaction of vegetable oil with `H_2SO_4` give glycerin
C. `C_2H_5OH`, iodine with NaOH gives iodoform
D. Sucrose on reaction with NaCl give invert sugar

Answer

To solve the question, we need to evaluate each of the four statements provided and determine which one is correct.

### Step-by-Step Solution:

1. **Evaluate Statement A**:
- The statement claims that "any aldehyde gives secondary alcohol on reduction."
- **Analysis**: When an aldehyde is reduced, it typically forms a primary alcohol. For example, if we take an aldehyde like CH3CHO (acetaldehyde) and reduce it, we get CH3CH2OH (ethanol), which is a primary alcohol.
- **Conclusion**: This statement is **incorrect**.

2. **Evaluate Statement B**:
- The statement claims that "the reaction of vegetable oil with H2SO4 gives glycerin."
- **Analysis**: When vegetable oils (which are triglycerides) are treated with H2SO4, they undergo hydrolysis to form fatty acids and glycerol. However, the primary products are unsaturated fatty acids, not glycerin directly.
- **Conclusion**: This statement is **incorrect**.

3. **Evaluate Statement C**:
- The statement claims that "C2H5OH (ethanol) with iodine and NaOH gives iodoform."
- **Analysis**: Ethanol does indeed react with iodine and NaOH to undergo oxidation to form acetaldehyde (CH3CHO), which can then react further to form iodoform (CHI3). This is a well-known reaction used in the iodoform test.
- **Conclusion**: This statement is **correct**.

4. **Evaluate Statement D**:
- The statement claims that "sucrose on reaction with NaCl gives invert sugar."
- **Analysis**: Invert sugar is typically produced by the hydrolysis of sucrose into glucose and fructose, often using acids or enzymes, not by reacting with NaCl. Therefore, no reaction occurs between sucrose and NaCl.
- **Conclusion**: This statement is **incorrect**.

### Final Answer:
The correct statement is **C**: "C2H5OH (ethanol) with iodine and NaOH gives iodoform."

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